#include<stdio.h>
int main(){
int n,i;
int sum=0;
printf("Enter
the n i.e. max values of series: ");
scanf("%d",&n);
sum
= (n * (n + 1) * (2 * n + 1 )) / 6;
printf("Sum of
the series : ");
for(i
=1;i<=n;i++){
if (i != n)
printf("%d^2 +
",i);
else
printf("%d^2 =
%d ",i,sum);
}
return 0;
}
Sample output:
Enter the n i.e. max values
of series: 5
Sum of the series: 1^2 + 2^2
+ 3^2 + 4^2 + 5^2 = 55
Mathematical Formula:
Sum of the series 12
+ 22 + 32 + … + n2 =
n (n+1) (2n+1)/6
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