Write a c program or code to find out the sum of series 1^3 + 2^3 + …. + n^3 that is sum of cube of n natural numbers.
#include<stdio.h>
#include<math.h>
int main(){
int n,i;
int sum=0;
printf("Enter
the n i.e. max values of series: ");
scanf("%d",&n);
sum = pow(((n * (n +
1) ) / 2),2);
printf("Sum of
the series : ");
for(i
=1;i<=n;i++){
if (i != n)
printf("%d^3 + ",i);
else
printf("%d^3 = %d ",i,sum);
}
return 0;
}
Sample
output:
Enter the n i.e. max values
of series: 3
Sum of the series: 1^3 + 2^3
+ 3^3 = 36
Mathematical
Formula:
Sum of the series 13 + 23 + 33 + … + n3 = (n (n+1)/2)2
0 comments:
Post a Comment